10 Tricky WASSCE Maths Questions Ghanaian Students Often Struggle With

10 Tricky WASSCE Maths Questions

Let us look at 10 tricky WASSCE Maths questions Ghanaian students often struggle with and, more importantly, how you can outsmart them. Let us see your answers in the comments section.

Bonus: How You Can Make Money In Ghana As A Student

1. Word Problems - WASSCE Maths Questions on Profits

Question: Ama buys oranges at ₵2 each and sells them at ₵2.50. If she sells 120 oranges, find her profit percentage.

Clue: Many candidates rush to calculate ₵0.50 × 120 without comparing cost and profit properly. Always remember to use the cost price as your base when solving profit-based WASSCE Maths questions.

2. Sets and Venn Diagrams

Question: In a class of 50 students, 30 like Maths, 28 like Science, and 10 like both. How many like neither?

Clue: Students forget to subtract the overlap before applying the union formula. This type of WASSCE Maths question checks both your logic and attention to detail.

3. Probability

Question: A fair die is thrown once. Find the probability of getting at least a 4.

Clue: Many students misinterpret “at least” as “exactly.” Always remember that WASSCE Maths questions on probability are all about carefully reading the wording.

4. Trigonometry Beyond the First Quadrant

Question: Find sin 240°.

Clue: Your calculator gives -0.866, but you must know the WASSCE Maths rule of quadrants (CAST diagram) to get the sign correct.

5. Indices and Surds

Question: Simplify √50 ÷ √2.

Clue: Many leave the answer as √25, but you must simplify it. Questions like this show how WASSCE Maths questions on surds reward students who simplify fully.

6. Mensuration in Word Problems

Question: A cylindrical tank of radius 7 metres is filled with water to a height of 3 metres. Find the volume in litres.

Clue: Students often forget to convert cubic metres to litres. WASSCE Maths questions on mensuration always test unit conversion.

7. Graphs and Slopes

Question: Find the slope of the line 2x + 3y = 6.

Clue: Unless you rearrange into y = mx + c, you may not see the slope clearly. These WASSCE Maths questions test whether you know the basics behind the formula.

 8. Bearings and Navigation

Question: A ship sails 80 km on a bearing of 045°. Draw a diagram and find its displacement east and north.

9. Logarithms with Hidden Bases

Question: Solve for x: log₂x = 5.

10. Word Problem

WASSCE Maths Questions On Speed, Distance, and Time

Question: A bus travels from Accra to Kumasi, a distance of 250 km, at an average speed of 80 km/h. On the return journey, it travels at an average speed of 100 km/h.

  1. How long did the bus take to travel from Accra to Kumasi?
  2. How long did it take for the return journey?
  3. Find the average speed of the bus for the whole journey.

Bonus: How You Can Make Money In Ghana As A Student

Conclusion

The secret to passing WASSCE Maths questions is not memorizing endless formulas, but learning exam-smart strategies. Practice past questions, pay attention to keywords like “at least,” “prove that,” or “neither”, and always write down steps clearly.

11 thoughts on “10 Tricky WASSCE Maths Questions Ghanaian Students Often Struggle With

  1. 1. Ghc2.50-2.00 =0.5
    120×0.5=Ghc60.00
    Total cost price=120×2=Ghc240.00
    Profit percentage =60/240 x 100% =25%

    2. Class =50 students, Maths=30,Science =28,Both=10
    Number of students who like at least one =30+28-10=48
    Number of student who doesn’t like neither =50-48
    =2 students

    3. Probability outcomes (4,5,6) =3/6=1/2
    4. Sin 240 =-sin 60° =- root3/2 =0.866
    5. Root 50 ÷root 2 =root 25 =5
    6. Volume=xr^2h=3.14×7^2x3m^3
    But 1m^3=1000L
    147 pi x1000=461,812 Litres
    7. 2x+3y=6
    3y=-2x+6
    y=-2/3x+2 slope =(-2/3)
    8. 80cos45°=40 root 2 or east =56.6 km north=56.6km
    9.log2x=5 x=2^5=32
    10.a.Time from Kumasi to Accra
    T=Distance/Speed=250/80=3.125h
    =3 hours 7.5 minutes
    B. Time from Kumasi to Accra
    T=Distance/Speed=250/100=2.5 hours
    2hours 30 minutes
    C. Average speed =total Distance/total Time
    =500/5.625
    =88.9km/h

    1. 1. Ghc2.50-2.00 =0.5
      120×0.5=Ghc60.00
      Total cost price=120×2=Ghc240.00
      Profit percentage =60/240 x 100% =25%

      2. Class =50 students, Maths=30,Science =28,Both=10
      Number of students who like at least one =30+28-10=48
      Number of student who doesn’t like neither =50-48
      =2 students

      3. Probability outcomes (4,5,6) =3/6=1/2
      4. Sin 240 =-sin 60° =- root3/2 =0.866
      5. Root 50 ÷root 2 =root 25 =5
      6. Volume=xr^2h=3.14×7^2x3m^3
      But 1m^3=1000L
      147 pi x1000=461,812 Litres
      7. 2x+3y=6
      3y=-2x+6
      y=-2/3x+2 slope =(-2/3)
      8. 80cos45°=40 root 2 or east =56.6 km north=56.6km
      9.log2x=5 x=2^5=32
      10.a.Time from Kumasi to Accra
      T=Distance/Speed=250/80=3.125h
      =3 hours 7.5 minutes
      B. Time from Kumasi to Accra
      T=Distance/Speed=250/100=2.5 hours
      2hours 30 minutes
      C. Average speed =total Distance/total Time
      =500/5.625
      =88.9km/h

    2. 1.25%
      2.2students
      3.2/3
      4.1/2
      5.5
      6.9234cm cube
      7.-2/3
      8.east= 56.6km
      north= 56.6km
      9.32
      10.
      A.3.125h
      B.6.25h
      C88.9km
      .

      1. Q.1
        Cost price=2.00
        Selling price=2.50
        Profit per orange=2.50-2.00
        =0.50
        Profit %=0.50/2.00×100
        25%

        Q2
        Total=50
        Maths=30
        Science=28
        Both=10
        Only Maths=30-10
        =20
        Only Science=28-10
        =18
        Total doing either=20+18+19
        =48

        Neither=50-48
        =2 students

        Q3
        Favourable outcomes=4,5,6
        Total outcomes=6
        3/6
        1/2

        Q4
        Sin240⁰
        Reference angle=240⁰-180⁰
        60⁰
        Sin240⁰=sin60⁰
        -3/2

        Q5
        √50/√2=-5√2/√2

        Q6
        V=π×1²×2

        6.28m³

        1m³=1000 litres
        Volume=6.28×1000
        6280 lites

        Q7
        2x+3y=6
        3y=-2x+6
        y=–2/3x+6/3
        y=-2/3x+2
        Slope=-2/3

        Q8
        East=80×cos45⁰
        80×0.7071
        56.57km
        North=80×sin45⁰
        80×0.7071
        56.57km

        Displacement=56.6km East and 56.6km North.

        Q9
        log2x=5
        2x=5
        2⁵=x
        2×2×2×2×2=32

        Q10
        Bus travels 250km
        A. Time to Kumasi= Distance/Speed
        250/80
        3.125 hours

        B. Return time= 250/100
        2.5 hours

        C. Total distance= 250+250
        500km
        Total time=3.125+2.5
        5.625 hours
        Average speed=Total distance/Total time
        500/5.625
        88.9km

  2. 1. 25%
    2. 2 students
    3. 1/6
    4. 27
    5. 5
    6. 462,000 L
    7. −2/3
    8.
    9. 32
    10. A. 3.125 h
    B. 2.5h
    C. 89km/hr

  3. 1. 33.3%
    2. 2
    3. ½
    4. -sin(60)
    5. 5
    6. 0.472 litres
    7. -⅔
    8. Both are 56.57Km
    9. 32
    10. A=3.125 hours
    B=2.5 hours
    C=88.89Km/h

  4. Q.1
    Cost price=2.00
    Selling price=2.50
    Profit per orange=2.50-2.00
    =0.50
    Profit %=0.50/2.00×100
    25%

    Q2
    Total=50
    Maths=30
    Science=28
    Both=10
    Only Maths=30-10
    =20
    Only Science=28-10
    =18
    Total doing either=20+18+19
    =48

    Neither=50-48
    =2 students

    Q3
    Favourable outcomes=4,5,6
    Total outcomes=6
    3/6
    1/2

    Q4
    Sin240⁰
    Reference angle=240⁰-180⁰
    60⁰
    Sin240⁰=sin60⁰
    -3/2

    Q5
    √50/√2=-5√2/√2

    Q6
    V=π×1²×2

    6.28m³

    1m³=1000 litres
    Volume=6.28×1000
    6280 lites

    Q7
    2x+3y=6
    3y=-2x+6
    y=–2/3x+6/3
    y=-2/3x+2
    Slope=-2/3

    Q8
    East=80×cos45⁰
    80×0.7071
    56.57km
    North=80×sin45⁰
    80×0.7071
    56.57km

    Displacement=56.6km East and 56.6km North.

    Q9
    log2x=5
    2x=5
    2⁵=x
    2×2×2×2×2=32

    Q10
    Bus travels 250km
    A. Time to Kumasi= Distance/Speed
    250/80
    3.125 hours

    B. Return time= 250/100
    2.5 hours

    C. Total distance= 250+250
    500km
    Total time=3.125+2.5
    5.625 hours
    Average speed=Total distance/Total time
    500/5.625
    88.9km

  5. 1. 25%
    2. 2
    3. ½
    4. -sin(60)
    5. 5
    6. 0.472 litres
    7. -⅔
    8.56.57Km
    9. 32
    10. A.3.125 hours
    b.2.5 hours
    c.88.89Km/h

Leave a Reply

Your email address will not be published. Required fields are marked *